Bromobis(isopropylthio)borane

Bromobis(isopropylthio)borane 化学特性,用途語,生産方法

• 合成

  To a stirred mixture of 3.57 g (0.010 mol) of bis(isopropylthio)lead2 in 20 mL of pentane under argon at 25 °C is added a solution of 0.95 mL (0.010 mol) of Boron Tribromide in 10 mL of pentane. After the mixture is stirred for 20 min, 10 mL of CH2Cl2 is added and the mixture is heated under reflux for 2.5 h. The reaction mixture is cooled to 25 °C and the white precipitate (PbBr2) is removed by filtration under argon. The filtrate is distilled under argon to remove solvents and then distilled under reduced pressure: 2.13 g Bromobis(isopropylthio)borane (90% yield) of a yellow oil; bp 75-80 °C/2 mmHg.

Bromobis(isopropylthio)borane 生産企業

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