Diisopropylammonium dichloroacetate is prepared by the reaction of dichloro-acetic acid and diisopropylamine. The steps are as follows:
1 volume of acetone is mixed with 1.5 volumes of cyclohexane to obtain a mixed solvent; Add 1 mol of diisopropylamine (101.19g, C6H15N, Mr=101.19) into 150ml of mixed solvent, stir evenly, and heat the liquid material to 50°C; slowly add 1mol of dichloroacetic acid (128.94g, C2H2Cl2O2, Mr=128.94) dropwise to the liquid material obtained in step (at a speed of about 10g/min) under heat preservation and stirring conditions,After the feeding is complete, keep warm and continue to stir for 3 hours, then naturally cool to 4-8°C, and then stand at this temperature for 10 hours; Filter the material obtained in step, separate the mother liquor, collect white crystals, and dry at 70° C. to obtain 216.8 g of the diisopropylamine dichloroacetate (C8H17Cl2NO2, Mr=230.13), with a molar yield of 94.2%.